[Video Solution] Let the function f(x)=\dfracx3+\dfrac3x+3,\ x\ne0 be strictly increasing in (... | ASPIRE STUDY

Name: [Video Solution] Let the function f(x)=\dfracx3+\dfrac3x+3,\ x\ne0 be strictly increasing in (... | ASPIRE STUDY
Uploaded: 2026-05-23T22:58:50+00:00
Description: Let the function f(x)=\dfracx3+\dfrac3x+3,\ x\ne0 be strictly increasing in (-\infty,α_1)\cup(α_2,\infty) and strictly decreasing in (α_3,α_4)\cup(α_4,α_5). Then \displaystyle ∑_i=1^5α_i^2 is equal to | Watch the step-by-step video solution for this NIMCET PYQ.

Let the function f(x)=\dfracx3+\dfrac3x+3,\ x\ne0 be strictly increasing in (-\infty,α_1)\cup(α_2,\infty) and strictly decreasing in (α_3,α_4)\cup(α_4,α_5). Then \displaystyle ∑_i=1^5α_i^2 is equal to | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-05-23T22:58:50+00:00 Thumbnail: Open Page: https://aspirediary.com/library/video/14973/let-the-function-f-x-dfracx3-dfrac3x-3-x-ne0-be-strictly-increasing-in

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