Aspire Faculty ID #18323 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

Let $A$ and $B$ be two points with position vectors $\vec a$ and $\vec b$ respectively and let $C$ be a point dividing $AB$ internally and the position vector of $C$ on $AB$ is $\vec c=\lambda \vec a+\mu \vec b$, then

Solution

Using section formula, $ \vec c=\frac{m\vec b+1\cdot \vec a}{m+1} $ Comparing with $\vec c=\lambda \vec a+\mu \vec b$, $ \lambda=\frac{1}{m+1},\ \mu=\frac{m}{m+1} $ $ \Rightarrow \lambda+\mu=\frac{1+m}{m+1}=1 $

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