Aspire Faculty ID #18314 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

The length $x$ of a rectangle is decreasing at the rate of $6$ cm/min and the width $y$ is increasing at the rate of $4$ cm/min. When $x=8$ cm and $y=4$ cm, the rate of change of the area of the rectangle is

Solution

$ A=xy $ $ \frac{dA}{dt}=x\frac{dy}{dt}+y\frac{dx}{dt} $ Given: $ \frac{dx}{dt}=-6,\ \frac{dy}{dt}=4 $ $ \frac{dA}{dt}=x(4)+y(-6) $ At $(8,4)$: $ \frac{dA}{dt}=8\cdot4-6\cdot4=32-24=8 $

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